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25x^2-27x+2=0
a = 25; b = -27; c = +2;
Δ = b2-4ac
Δ = -272-4·25·2
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-23}{2*25}=\frac{4}{50} =2/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+23}{2*25}=\frac{50}{50} =1 $
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